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(a) `u_r=0`, `a_r=g` <br> `:. v_r=sqrt(2gh_1)` <br> After collision relative velocity <br> `v_r^()'=esqrt(2gh_1)` <br> and relative retardation is still g (downwards). <br> Hence, <br> `h_2=((v_r^()')^2)/(2g)=e^2h_1` <br> (b) `u_r=0`, `a_r=g+g/4=(5g)/(4)` <br> `:.` Just before collsion `v_r=sqrt(2((5g)/(4))h_1)` <br> Just after collision `v_r^()'=ev_r`. <br> Relative retardation is still `(5g)/(4)`. <br> Hence, `h_2=((v_r^()')^2)/(2((5g)/(4)))=e^2h_1`